The product of the following reaction is:

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(B) The reaction involves the protonation of the exocyclic double bond of $1$-methylenecyclohexa-$2,5$-diene. This leads to the formation of a resonan

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(B) The reaction involves the protonation of the exocyclic double bond of $1$-methylenecyclohexa-$2,5$-diene. This leads to the formation of a resonance-stabilized carbocation intermediate. Subsequent loss of a proton $(H^+)$ from the $sp^3$ hybridized carbon results in the formation of the aromatic compound,toluene $(C_6H_5CH_3)$.

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